PARADISCYL:Cylinder-Remove surface debris: Difference between revisions
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There is remaining issue realted to the time step due to the small dislocation segments.This tutorial describes how to remove tiny dislocation segment in cylinder code. |
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When two dislocations meet near the surface and form a junction, it would generate very tiny segments, which occur rapid drop in time step. To overcome this issue,we remove these small dislocation segment according to the following algorithm. |
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==Algorithm== |
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1. Searching for the surface node(node in Figure 1.(a)) |
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2. Find the neighbor node(nbr1 in Figure 1.(a)) |
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3. Check if ''seglength'' is less than ''minSeg'' |
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4. Count the number of independent slip planes of inside arms. |
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''Case I'':if nbr1 has a independent slip plane and nbr1 has 3, 2 of which are linked to surface |
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-> Project nbr1 to the surface along the line(See figure 1.(b)) |
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''Case II'':if nbr1 has 2 independent slip planes |
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Project nbr1 to surface along the intersection of two slip planes(See figure 1.(c)) |
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|[[Image:Remove_surface_debris1.jpg |frameless|200px|caption]] |
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|[[Image:Remove_surface_debris2.jpg |frameless|200px|caption]] |
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|[[Image:Remove_surface_debris3.jpg |frameless|200px|caption]] |
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|align="center"|(a) |
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|align="center"|(b) |
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|align="center"|(c) |
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|colspan="2" | Fig.1 (a)Schematic diagram (b) Case ''I'' (c) Case ''II''. |
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Latest revision as of 08:14, 8 December 2011
Remove surface debris
ill Ryu and Wei Cai
There is remaining issue realted to the time step due to the small dislocation segments.This tutorial describes how to remove tiny dislocation segment in cylinder code.
When two dislocations meet near the surface and form a junction, it would generate very tiny segments, which occur rapid drop in time step. To overcome this issue,we remove these small dislocation segment according to the following algorithm.
Algorithm
1. Searching for the surface node(node in Figure 1.(a))
2. Find the neighbor node(nbr1 in Figure 1.(a))
3. Check if seglength is less than minSeg
4. Count the number of independent slip planes of inside arms.
Case I:if nbr1 has a independent slip plane and nbr1 has 3, 2 of which are linked to surface -> Project nbr1 to the surface along the line(See figure 1.(b))
Case II:if nbr1 has 2 independent slip planes Project nbr1 to surface along the intersection of two slip planes(See figure 1.(c))
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| (a) | (b) | (c) |
| Fig.1 (a)Schematic diagram (b) Case I (c) Case II.
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